Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.6 - Rational Equations - Concept and Vocabulary Check - Page 462: 6

Answer

The fill in the blank is $ 5(x+3)+3(x+4) = 12x+9$.

Work Step by Step

The given expression is $(x+4)(x+3)\left( \frac{5}{x+4}+\frac{3}{x+3} \right) = (x+4)(x+3)\left( \frac{12x+9}{(x+4)(x+3)} \right)$ Use the distributive property. $ (x+4)(x+3)\cdot\frac{5}{x+4}+(x+4)(x+3)\cdot\frac{3}{x+3} = (x+4)(x+3)\cdot\frac{12x+9}{(x+4)(x+3)} $ Cancel common terms. $ 5(x+3)+3(x+4) = 12x+9$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.