Answer
$\dfrac{2x-1}{x+3}$
Work Step by Step
Since,in the given rational expressions denominator are same, thus take it as common and add the rational terms simply.
Given: $\dfrac{x^2-2x}{x^2+3x}+\dfrac{x^2+x}{x^2+3x}$
or, $=\dfrac{x^2-2x+x^2+x}{x^2+3x}$
or, $=\dfrac{2x^2-x}{x^2+3x}$
or, $=\dfrac{x(2x-1)}{x(x+3)}$
or, $=\dfrac{2x-1}{x+3}$
