Answer
-3/5, -1/4, 15/8
Work Step by Step
$\frac{2(-1)^3-1}{(-1)^2+4} = \frac{-2-1}{5} = -\frac{3}{5}$
$\frac{2(-1)^3-1}{(-1)^2+4} = \frac{-2-1}{5} = -\frac{1}{4}$
$\frac{2(2)^3-1}{(2)^2+4} = \frac{2(8)-1}{4+4} = \frac{15}{8}$
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