Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 286: 127

Answer

The graph is shown below.

Work Step by Step

The given linear equation is $\Rightarrow f(x)=-\frac{2}{3}x$ The equation is in the form of $f(x)=mx+b$ Where, $m$ is the slope and $b$ is the $y-$ intercept. From the equation slope is $-\frac{2}{3}$. and $y-$ intercept is $0$. Now plot the point $(0,0)$. For the second point use rise over run, $\Rightarrow m = -\frac{2}{3}= \frac{-2}{3}=\frac{Rise}{Run}$ By using slope the next point is $2$ units down and $3$ units to the right. Hence, the second point is $(3,-2)$ Draw a straight line through the two points.
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