Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 283: 55

Answer

$[-5,3]$. The graph is shown below.

Work Step by Step

The given expression is $\Rightarrow \left | 2(x-1)+4\right |\leq8$ Rewrite the inequality without absolute value bars. $\Rightarrow -8\leq 2(x-1)+4\leq8$ Solve compound inequality. Add $-4$ to all three parts. $\Rightarrow -8-4\leq 2(x-1)+4-4\leq8-4$ Simplify. $\Rightarrow -12\leq 2(x-1)\leq4$ Divide all three parts by $2$. $\Rightarrow \frac{-12}{2}\leq \frac{2(x-1)}{2}\leq\frac{4}{2}$ Simplify. $\Rightarrow -6\leq x-1\leq2$ Add $1$ to all three parts. $\Rightarrow -6+1\leq x-1+1\leq2+1$ Simplify. $\Rightarrow -5\leq x\leq3$ The solution set $[-5,3]$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.