Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.4 - Matrix Solutions to Linear Systems - Exercise Set - Page 228: 4

Answer

The answer is $\left(\begin{array}{cc|c} 1 & -\frac{3}{2} & 5 \\ 4 & 2 & 5 \\ \end{array}\right)$.

Work Step by Step

The given matrix is $\left(\begin{array}{cc|c} -2 & 3 & -10 \\ 4 & 2 & 5 \\ \end{array}\right)$ Perform $ -\frac{1}{2}R_1 $. Multiply row 1 by $ -\frac{1}{2} $. $\left(\begin{array}{cc|c} -2\cdot (-\frac{1}{2}) & 3\cdot (-\frac{1}{2}) & -10\cdot (-\frac{1}{2}) \\ 4 & 2 & 5 \\ \end{array}\right)$ Simplify. $\left(\begin{array}{cc|c} 1 & -\frac{3}{2} & 5 \\ 4 & 2 & 5 \\ \end{array}\right)$.
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