Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 204: 7

Answer

$x=500, P(x)=140x-70000$

Work Step by Step

Given: $C(x)=105x+70000$ and $R(x)=245x$ After equating the given two equation, we get $140x=70000$ or, $x=500$ Now, $P(x)=245x-(105x+70000)$ or, $P(x)=140x-70000$ Thus, $x=500, P(x)=140x-70000$
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