Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Review Exercises - Page 172: 5

Answer

a) 2 b) 52 c) 70 d) $3*b^2-5b+2$ e) $48a^2-20a+2$

Work Step by Step

To find the function value we simply substitute x for the value given a) $g(0)=3*0-5*0+2=2$ b) $g(5)=3*5^2-5*5+2=52$ c) $g(-4)=3*(-4)^2-5*(-4)+2=70$ d) $g(b)=3*b^2-5b+2$ e) $g(4a)=3*(4a)^2-5*4a+2=48a^2-20a+2$
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