Answer
$a_1=\frac{3}{4}
\\a_2=\frac{1}{2}
\\a_3 =\frac{1}{4}
\\a_4 =0
\\a_5 =-\frac{1}{4}
\\a_6 =-\frac{1}{2}$
Work Step by Step
The next five terms f the sequence can be found by adding the common difference to obtain:
$a_1=\frac{3}{4}
\\a_2=\frac{3}{4}+(−\frac{1}{4})=\frac{2}{4}=\frac{1}{2}
\\a_3 = \frac{2}{4}+ (-\frac{1}{4})=\frac{1}{4}
\\a_4 = \frac{1}{4}+(-\frac{1}{4})=0
\\a_5 = 0 +(-\frac{1}{4})=-\frac{1}{4}
\\a_6 = -\frac{1}{4}+(-\frac{1}{4}) = -\frac{2}{4}=-\frac{1}{2}$
