Answer
{$(1,0), (4,3)$}
Work Step by Step
Since, we have first equation: $5y=x^2-1$ and second equation: $x-y=1$
From the first equation, we have
$5(x-1)=x^2-1$
or, $x^2-5x+4=0$
or, $(x-4)(x-1)=0$
Thus, $x=${$1,4$}
From the second equation, we have
$1-y=1$
or, $y=0$
Thus, $y=0$
Now, $4-y=1 \implies y=3$
Hence, the solution set: {$(1,0), (4,3)$}
