Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.7 - Scientific Notation - Exercise Set - Page 90: 57

Answer

$x=-3.6\times10^{5}$

Work Step by Step

Divide equation with $(-1.2\times10^{-3}).$ $x=\frac{(1.8\times10^{-4})(2.4\times10^{6})}{-1.2\times10^{-3}}$ $x=(\frac{1.8\times2.4}{-1.2})\times(\frac{10^{-4}\times10^{6}}{10^{-3}})$ $x=-3.6\times10^{-4+6-(-3)}=-3.6\times10^{5}$
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