Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises - Page 98: 45

Answer

$10x$

Work Step by Step

Simplify within the grouping symbols first to obtain: $=8-2[3-5x-(-1)] \\=8-2[3-5x+1] \\=8-2(-5x+4)$ Distribute the 2 to obtain: $=8 - 2(-5x) -2(4) \\=8 + 10x - 8$ Combine like terms to obtain: $=10x + (8-8) \\=10x$
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