Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 2 - Systems of Linear Equations and Inequalities - 2.1 Systems of Linear Equations - 2.1 Exercises - Page 142: 41

Answer

See sample answer below.

Work Step by Step

We need two lines that pass through (2,4). Take one line with b=0, $y=mx+0\quad $ ... substitute x and y $4=m\cdot 2\quad $ ... divide by 2 $2=m\quad $... so our first line is $y=2x$ For our second line, take the horizontal line $y=4$. The point (2,4) lies on both lines , so $(2,4)$ is the solution to $\left\{\begin{array}{l} y=2x\\ y=4 \end{array}\right.$ .
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