Answer
See sample answer below.
Work Step by Step
We need two lines that pass through (2,4).
Take one line with b=0,
$y=mx+0\quad $ ... substitute x and y
$4=m\cdot 2\quad $ ... divide by 2
$2=m\quad $... so our first line is $y=2x$
For our second line, take the horizontal line $y=4$.
The point (2,4) lies on both lines , so $(2,4)$ is the solution to
$\left\{\begin{array}{l}
y=2x\\
y=4
\end{array}\right.$
.