Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Sections 9.1-9.6 - Integrated Review - Functions and Properties of Logarithms - Page 580: 19

Answer

Please see the graph.

Work Step by Step

$y=\log_{1/3}x$ $y=\log_{1/3}x$ $x=(1/3)^y$ $y=-1$ $x=(1/3)^y$ $x=(1/3)^{-1}$ $x=1/(1/3)$ $x=3$ $y=-2$ $x=(1/3)^y$ $x=(1/3)^{-2}$ $x=(1/(1/3))^2$ $x=1^2/(1/3)^2$ $x=1/(1/9)$ $x=9$ $(3,-1)$ and $(9,-2)$ are on the curve.
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