Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 592: 70

Answer

10

Work Step by Step

We start with $13,500,000=12,830,000e^{.005t}$ This gives: $1.052=e^.005t$ Using the natural log function, we get: $.005t=ln(1.052)$ $t=10$
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