Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.5 - Quadratic Functions and Their Graphs - Exercise Set - Page 520: 79a

Answer

119,141 million

Work Step by Step

$f(x)=2158x^2-10339x+6731$ $2010-2000=10$ $x=10$ $f(x)=2158x^2-10339x+6731$ $f(10)=2158*10^2-10339*10+6731$ $f(10)=2158*100-103390+6731$ $f(10)=215800-103390+6731$ $f(10)=119141$
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