Answer
$2x^{n+2}+4x^2$
Work Step by Step
Factor the numerators and the denominators, when needed to have:
$\\=\dfrac{(x^n-2)(x^n+2)}{7x} \cdot \dfrac{7x(2x^2)}{x^n-2}$
Cancel the common factors to have:
$\\\require{cancel}=\dfrac{\cancel{(x^n-2)}(x^n+2)}{\cancel{7x}} \cdot \dfrac{\cancel{7x}(2x^2)}{\cancel{x^n-2}}
\\=(x^n+2)(2x^2)
\\=2x^2(x^n)+2x^2(2)
\\=2x^{n+2}+4x^2$
