Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.4 - Multiplying Polynomials - Graphing Calculator Explorations - Page 288: 4

Answer

Choice A

Work Step by Step

The highest degree of the product of the given expression, $ (3x-1)(4x^2-2x+1) ,$ is obtained by multiplying the first terms of the given factors. That is, \begin{array}{l} 3x(4x^2) \\\\= 12x^3 \end{array} With an exponent of $3$, then the polynomial is of degree 3. Hence, Choice A.
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