Answer
$3x^{2}-12x+13$
Work Step by Step
We are given that $Q(x)=4x^{2}-6x+3$ and $R(x)=5x^{2}-7$.
$2[Q(x)]-R(x)=2(4x^{2}-6x+3)-(5x^{2}-7)=(8x^{2}-12x+6)+(-5x^{2}+7)$
Combine like terms.
$(8x^{2}-5x^{2})-12x+(6+7)=3x^{2}-12x+13$
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