Answer
$\dfrac{a^3}{64}$
Work Step by Step
Using laws of exponents, then,
\begin{array}{l}
(4a^{-1}b^0)^{-3}
\\\\=
4^{-3}a^{-1(-3)}
\\\\=
\dfrac{a^3}{4^{3}}
\\\\=
\dfrac{a^3}{64}
.\end{array}
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 5 - Cumulative Review - Page 334: 40a
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
