Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.1 - Sequences - Exercise Set - Page 640: 58

Answer

multiple answers; see details

Work Step by Step

Given that $ a_n=\left( 1+\dfrac{0.05}{n} \right)^n $, then, \begin{array}{l} a_1=\left( 1+\dfrac{0.05}{1} \right)^1 =1.05 ,\\\\ a_2=\left( 1+\dfrac{0.05}{2} \right)^2 \approx 1.0506 ,\\\\ a_3=\left( 1+\dfrac{0.05}{3} \right)^3 \approx 1.0508 ,\\\\ a_4=\left( 1+\dfrac{0.05}{4} \right)^4 \approx 1.0509 ,\\\\ a_5=\left( 1+\dfrac{0.05}{5} \right)^5 \approx 1.0510 .\end{array}
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