Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.1 - Sequences - Exercise Set - Page 639: 39

Answer

$48ft$ $ 80ft$ $ 112ft$

Work Step by Step

$a_{n}= 32n-16$ The distance, the Thermos falls in the first second, $a_{1}= 32(1)-16 = 32-16 = 16 ft$ The distance, the Thermos falls in the second second, $a_{2}= 32(2)-16 = 64-16 = 48 ft$ The distance, the Thermos falls in the third second, $a_{3}= 32(3)-16 = 96-16 = 80 ft$ The distance, the Thermos falls in the fourth second, $a_{4}= 32(4)-16 = 128-16 = 112 ft$
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