Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Sections 10.1-10.2 - Integrated Review - Graphing Conic Sections - Page 620: 14

Answer

See graph

Work Step by Step

$y^2=x^2+16$ $y^2-x^2=16$ $\frac{y^2}{16}-\frac{x^2}{16}=1$ This will be a hyperbola.
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