Answer
Please see the graph.
Work Step by Step
The red graph is $ y>x^{2}$, and the blue graph is $ y\ge2x+1$.
$y > x^2$
Since we have a greater than sign, we use a dotted line. We also pick the point $(0,2)$ to determine what side of the line to shade.
$y \ge 2x+1$
Since we have a greater than or equal to sign, we use a solid line. We also pick the point $(0,2)$ to determine what side of the line to shade.
$(0,2)$
$y > x^2$
$2 > 0^2$
$2 > 0$ (true, so we shade the side of the graph with the point)
$(0,2)$
$y \ge 2x+1$
$2 \ge 2*0+1$
$2 \ge 0+1$
$2 \ge 1$ (false, so we shade the side of the graph without the point)
The overlap of the two graphs is the solution set.
