Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Section 10.2 - The Ellipse and the Hyperbola - Graphing Calculator Explorations - Page 617: 4

Answer

See graph

Work Step by Step

$4y^2+12x^2=48$ $y^2+3x^2=12$ $y=\sqrt{12-3x^2},-\sqrt{12-3x^2}$ Enter these two equations into Y1 = and Y2=. Then press graph.
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