Answer
$x=\frac{1}{6}y+3$
Work Step by Step
$3x-\frac{1}{2}y=9$
$(3x-\frac{1}{2}y)+\frac{1}{2}y=(9)+\frac{1}{2}y$
$3x=\frac{1}{2}y+9$
$(3x)/3=(\frac{1}{2}y+9)/3$
$x=\frac{1}{6}y+3$
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