Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 9 - Inequalities and Problem Solving - Mid-Chapter Review - Mixed Review - Page 602: 7

Answer

$$2 \lt x \lt 11$$

Work Step by Step

We solve the inequalities using the rules of inequalities. These are the same as if there were an equal sign instead of an inequality symbol, but note that the inequality symbol must be flipped if we multiply or divide both sides by a negative. Doing this, we obtain: $$ -1<10-x<8\\ -1<10-x\quad \mathrm{and}\quad \:10-x<8\\ x<11\quad \mathrm{and}\quad \:x>2\\ 2 \lt x \lt 11$$
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