Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 13 - Conic Sections - Mid-Chapter Review - Guided Solutions - Page 873: 2

Answer

Hyperbola.

Work Step by Step

${{x}^{2}}-\frac{{{y}^{2}}}{25}=1$ Therefore, both variables are squared, so the graph is not a parabola. The subtraction sign indicates that the provided equation ${{x}^{2}}-\frac{{{y}^{2}}}{25}=1$ is a hyperbola. We also know that: $y=\frac{b}{a}x$ and $y=-\frac{b}{a}x$ where $a$ and $b$ are the $x\text{-intercept}$ and $y\text{-intercept}$ of the hyperbola, respectively. Substitute $5$ for $a$ and $-5$ for $b$ in the formula: $y=5x$ and $y=-5x$ Thus, the provided equation ${{x}^{2}}-\frac{{{y}^{2}}}{25}=1$ is a hyperbola with asymptotes $y=5x$ and $y=-5x$. The intersecting points are calculated as follows: Substitute $y=0$ in the provided equation ${{x}^{2}}=1$ Taking the square root on both sides: $x=\pm 1$ Thus, the graph passes through the points $\left( 1,0 \right)$ and $\left( -1,0 \right)$. Now graph the equation.
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