Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Study Summary - Practice Exercises - Page 842: 10

Answer

$19$

Work Step by Step

In order to simplify $\log_{6}6^{19}$ we will use properties: $$\log_{a}a=1 \text{ and } \log_{a}M^{p}=p\cdot\log_{a}M$$ So $$\log_{6}6^{19}=19\log_{6}6=19\cdot 1=19$$
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