Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - Mid-Chapter Review - Mixed Review - Page 812: 3

Answer

$x^{2}-10x+26$

Work Step by Step

$(f\circ g)(x)=f[g(x)]=[g(x)]^{2}+1$ $=(x-5)^{2}+1$ $=x^{2}-10x+25+1$ $=x^{2}-10x+26$
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