Chapter 9 - Roots and Radicals - Chapters 1-9 Cumulative Review Problem Set - Page 433: 63

$x+4y=-12$

The slope-intercept form of a straight line is $y=mx+b$, where $m$ is the slope and $b$ is the y-intercept. Since the values of $m$ and $b$ are given in the question, we substitute these values into the equation: $y=mx+b$ $y=-\frac{1}{4}x-3$ $y=\frac{-1x-3(4)}{4}$ $y=\frac{-1x-12}{4}$ $4y=-x-12$ $x+4y=-12$ Therefore, the equation of the line is $x+4y=-12$.