Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapter 9 Test - Page 431: 3

Answer

$\approx 2.8$

Work Step by Step

Using $\sqrt{2}=1.41$ and the properties of radicals, the given expression, $ \sqrt{8} ,$ evaluated to the nearest tenth, is equal to: \begin{array}{l}\require{cancel} \sqrt{4\cdot2} \\\\= \sqrt{(2)^2\cdot2} \\\\= 2\sqrt{2} \\\\= 2(1.41) \\\\ \approx 2.8 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.