Chapter 9 - Roots and Radicals - 9.5 - Solving Radical Equations - Problem Set 9.5 - Page 425: 52

{$4$}

Step 1: $\sqrt[3] {x-12}=-2$ Step 2: Raising each side of the equation to the power of $3$ and simplifying, we obtain: $(\sqrt[3] {x-12})^{3}=(-2)^{3}$ $x-12=-8$ Step 3: Solving the equation, we obtain: $x-12=-8$ $x=-8+12$ $x=4$ Therefore, the solution set of the equation is {$4$}.