Chapter 8 - Coordinate Geometry and Linear Systems - 8.3 - Slope of a Line - Problem Set 8.3 - Page 349: 14

$m=-\dfrac{4}{3}$

Using $m=\dfrac{y_1-y_2}{x_1-x_2}$, the slope of the line determined by the given points, $( -8,-3 ) \text{ and } ( -2,-11 ),$ is \begin{array}{l}\require{cancel} m=\dfrac{-3-(-11)}{-8-(-2)} \\\\ m=\dfrac{-3+11}{-8+2} \\\\ m=\dfrac{8}{-6} \\\\ m=\dfrac{\cancel{2}\cdot4}{\cancel{2}\cdot(-3)} \\\\ m=\dfrac{4}{-3} \\\\ m=-\dfrac{4}{3} .\end{array}