Answer
$\frac{1}{x^{3}y^{2}}$
Work Step by Step
Using the rule $\frac{x^{a}}{x^{b}}=x^{a-b}$, we obtain:
$\frac{x^{4}y^{3}}{x^{7}y^{5}}=x^{4-7}y^{3-5}=x^{-3}y^{-2}=\frac{1}{x^{3}y^{2}}$
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