Answer
$3(n-5)(n+6)$
Work Step by Step
Using the rules of factoring trinomials to factor the polynomial, we obtain:
$3n^{2}+3n-90$
=$3(n^{2}+n-30)$
=$3(n^{2}-5n+6n-30)$
=$3[n(n-5)+6(n-5)]$
=$3(n-5)(n+6)$
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