Answer
$n\gt\dfrac{5}{11}$
Work Step by Step
Multiplying both sides by the $LCD=
30
$ and then using the properties of inequalities, the solution to the given inequality, $
\dfrac{n+4}{5}+\dfrac{n-3}{6}\gt\dfrac{7}{15}
,$ is
\begin{array}{l}\require{cancel}
6(n+4)+5(n-3)\gt2(7)
\\\\
6n+24+5n-15\gt14
\\\\
6n+5n\gt14-24+15
\\\\
11n\gt5
\\\\
n\gt\dfrac{5}{11}
.\end{array}