Answer
2500 dollars were invested at 4%.
4000 dollars were invested at 6%.
Work Step by Step
Let X represent the amount invested at 4%.
1500 more than that amount is invested at 6%, which means that X + 1500 is invested at 6%.
The interest from the first investment is 4% $\times$ X = 0.04X
The interest from the second investment is 6% $\times$ (X + 1500) = 0.06X + 90
Because the interest from the two investments is 340 dollars, we create and
solve the following equation:
0.04X + 0.06X + 90 = 340
0.1X + 90 = 340
0.1X = 250
Divide both sides by 0.1
X = 2500
2500 dollars were invested at 4%.
2500 + 1500 = 4000 dollars were invested at 6%.
