Chapter 3 - Equations and Problem Solving - 3.1 - Solving First-Degree Equations - Problem Set 3.1 - Page 100: 55

$y=-\dfrac{1}{3}$

Multiplying both sides by the $LCD= 6 ,$ and using the properties of equality, the value of the variable that satisfies the given equation, $ \dfrac{-y}{2}=\dfrac{1}{6} ,$ is \begin{array}{l}\require{cancel} 3(-y)=1(1) \\\\ -3y=1 \\\\ y=\dfrac{1}{-3} \\\\ y=-\dfrac{1}{3} .\end{array}