Answer
1
Work Step by Step
We follow order of operations, so we first consider everything inside of the brackets, and then we add/subtract everything else:
$6-[3-(10-12)]$
=$6-[3-(-2)]$
=$6-[3+2]$
=$6-5$
=$1$
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 2 - Real Numbers - Chapters 1-2 Cumulative Review Problem Set - Page 91: 3
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