Answer
{$-\frac{1}{3},2$}
Work Step by Step
Using the rules of factoring trinomials to factor, we obtain:
$3x^{2}-5x-2=0$
$3x^{2}+1x-6x-2=0$
$x(3x+1)-2(3x+1)=0$
$(3x+1)(x-2)=0$
$(3x+1)=0$ or $(x-2)=0$
$x=-\frac{1}{3}$ or $x=2$
Therefore, the solution set is {$-\frac{1}{3},2$}.
