Answer
{$-1,4$}
Work Step by Step
Using the rules of factoring trinomials to factor, we obtain:
$a^{2}-3a-4=0$
$a^{2}+1a-4a-4=0$
$a(a+1)-4(a+1)=0$
$(a+1)(a-4)=0$
$(a+1)=0$ or $(a-4)=0$
$a=-1$ or $a=4$
Therefore, the solution set is {$-1,4$}.
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 11 - Additional Topics - 11.5 - Quadratic Equations: Complex Solutions - Problem Set 11.5 - Page 496: 11
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