Answer
False
Work Step by Step
RECALL:
For any real number $a$,
$|a| \ge 0$
This means that the absolute value of any number is greater than or equal to 0.
Thus, for any real number $x$, $|x+1| \ge 0$.
Therefore,
$|x+1| \not \lt -3$
The given inequality has no solution.
Thus, the given statement is false.
