Answer
Two possibilities:
Jay went 45 mph and Jean went 48 mph
OR
Jay went 7.5 mph and Jean went 10.5 mph
Work Step by Step
Recall that velocity is equal to change in distance over change in time. We call t the time it takes Jay. Thus, we obtain:
$\frac{336}{t+2} = \frac{225}{t} + 3 $
We create common denominators and solve for t:
$ \frac{336t}{t(t+2)} = \frac{225(t+2)}{t(t+2)} + \frac{3t(t+2)}{t(t+2)}$
Since the denominators are the same, we cancel them out and solve. (Recall, t cannot be negative.)
$ 0 = (t-30)(t-5)$
Since both values yield positive results, we must consider both:
$ v_{Jay} = 225 / 30 = 7.5 $
$ v_{Jean} = 7.5 + 3 = 10.5$
OR
$v_{Jay} = 225/5 = 45$
$ v_{Jean} = 45 + 3 = 48$
