Answer
$\displaystyle \frac{4x^{2}-3x-7}{2x-1}=2x-0.5+\frac{-7.5}{2x-1}$
Work Step by Step
$\left[\begin{array}{l}
\\
2x-1\\
\\
\\
\\
\\
\\
\\
\end{array}\right. $ $\left.\begin{array}{rrrrrr}
2x & -0.5 & & & \\
\hline)\
4x^{2} & -3x & -7 & & \\
4x^{2} & -2x & & & \\
-- & -- & & & \\
& -x & -7 & & \\
& -x & +0.5 & & \\
& -- & -- & & \\
& & -7.5 & &
\end{array}\right]$
$Q(x)=2x-0.5,\quad R(x)=-7.5$
In the form $ \displaystyle \frac{P(x)}{D(x)}=Q(x)+\frac{R(x)}{D(x)},$
$\displaystyle \frac{4x^{2}-3x-7}{2x-1}=2x-0.5+\frac{-7.5}{2x-1}$
