College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.8 - One-to-One Functions and their Inverses - 2.8 Exercises - Page 262: 43

Answer

f and g are inverses

Work Step by Step

g(f(x)) = g($x^{2}$ - 9) = $\sqrt {x^{2} - 9 + 9}$ =$ \sqrt {x^{2}}$ = x f(g(x)) = $f(\sqrt {x + 9})$ = ${(\sqrt {x + 9})^{2}}$ - 9 = x + 9 - 9 = x Since g(f(x)) = f(g(x)) are equal to each other, f and g are inverses
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.