College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Section 2.6 - Transformations of Functions - 2.6 Exercises - Page 243: 61

Answer

$y=2(x-3)^2-2$

Work Step by Step

We begin with: $f(x)=x^2$ We are told to stretch vertically by a factor of 2, shift down 2 units, and shift 3 units right. This means: $y=2f(x-3)-2$. Thus we get: $y=2(x-3)^2-2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.