College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 2, Functions - Chapter 2 Review - Exercises - Page 270: 80

Answer

The maximum profit: $88500$ $x=15000$ units must be sold to generate the maximum profit

Work Step by Step

$P(x)=-0.0004x^2+12x-1500$, To find the maximum profit, we can turn an equation from a standard form into a vertex form by completing the square. $P(x)=-0.0004(x^2-30000x)-1500$, $-0.0004(x^2-30000x+225000000)-1500$, for an equation to match the previous one just as we added $-0.0004(225000000)$ into the equation we need to subtract $-0.0004(225000000)$ from an equation, thus,$P(x)=-0.0004(x^2-30000x+225000000)-1500-(-0.0004(225000000))$ $P(x)=-0.0004(x-15000)^2+88500$, Therefore, we can see that from an equation the maximum profit is $88500$ and $x=15000$ units must be sold to generate the maximum profit.
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