College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 7 - Summary, Review, and Test - Cumulative Review Exercises (Chapters 1-7) - Page 7074: 2

Answer

$x\lt2$

Work Step by Step

Distribute both sides, and then add like terms. Then subtract $12$ and $12x$ on both sides and divide. Make sure to flip the sign since you are dividing by a negative. $-3(2x-4)\gt2(6x-12)$ $-6x+12\gt12x-24$ $-18x\gt-36$ $x\lt2$
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