Answer
$(2,-6),(-2,10)$
Work Step by Step
$$\begin{cases}
y=x^2-4x-2\\
y=-4x+2
\end{cases}$$
Equate the expressions and solve for $x$ using the substitution method:
$$x^2-4x-2=-4x+2$$
$$x^2-2=2$$
$$x^2=4$$
$$x=\pm\sqrt4=\pm2$$
Determine $y$:
$$y_1=-4(2)+2=-6$$
$$y_2=-4(-2)+2=10$$
The solutions are:
$$(2,-6),(-2,10)$$
